Consider the following frequency distribution:

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | c | c | }
\hline
Value & 4 & 5 & 8 & 9 & 6 & 12 & 11 \\
\hline
Frequency & 5 & $f _ { 1 }$ & $f _ { 2 }$ & 2 & 1 & 1 & 3 \\
\hline
\end{tabular}
\end{center}

Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.
For the given frequency distribution, let $\alpha$ denote the mean deviation about the mean, $\beta$ denote the mean deviation about the median, and $\sigma ^ { 2 }$ denote the variance.

Match each entry in List-I to the correct entry in List-II and choose the correct option.

\section*{List-I}
(P) $7 f _ { 1 } + 9 f _ { 2 }$ is equal to\\
(Q) $19 \alpha$ is equal to\\
(R) $19 \beta$ is equal to\\
(S) $19 \sigma ^ { 2 }$ is equal to

\section*{List-II}
(1) 146\\
(2) 47\\
(3) 48\\
(4) 145\\
(5) 55

\begin{center}
\begin{tabular}{|l|l|l|l|l|}
\hline
(A) & $( \mathrm { P } ) \rightarrow ( 5 )$ & $( \mathrm { Q } ) \rightarrow ( 3 )$ & $( \mathrm { R } ) \rightarrow ( 2 )$ & $( \mathrm { S } ) \rightarrow ( 4 )$ \\
\hline
(B) & $( \mathrm { P } ) \rightarrow ( 5 )$ & $( \mathrm { Q } ) \rightarrow ( 2 )$ & $( \mathrm { R } ) \rightarrow ( 3 )$ & $( \mathrm { S } ) \rightarrow ( 1 )$ \\
\hline
(C) & $( \mathrm { P } ) \rightarrow ( 5 )$ & $( \mathrm { Q } ) \rightarrow ( 3 )$ & $( \mathrm { R } ) \rightarrow ( 2 )$ & $( \mathrm { S } ) \rightarrow ( 1 )$ \\
\hline
(D) & $( \mathrm { P } ) \rightarrow ( 3 )$ & $( \mathrm { Q } ) \rightarrow ( 2 )$ & $( \mathrm { R } ) \rightarrow ( 5 )$ & $( \mathrm { S } ) \rightarrow ( 4 )$ \\
\hline
\end{tabular}
\end{center}