Two springs of force constants $300 \mathrm {~N} / \mathrm { m }$ (Spring A) and $400 \mathrm {~N} / \mathrm { m }$ (Spring B) are joined together in series. The combination is compressed by 8.75 cm . The ratio of energy stored in A and B is $\frac { E _ { A } } { E _ { B } }$. Then $\frac { E _ { A } } { E _ { B } }$ is equal to:\\
(1) $\frac { 4 } { 3 }$\\
(2) $\frac { 16 } { 9 }$\\
(3) $\frac { 3 } { 4 }$\\
(4) $\frac { 9 } { 16 }$