Let $y(x)$ be the solution of the differential equation $(x \log x) \frac{dy}{dx} + y = 2x \log x$, $(x \geq 1)$. Then $y(e)$ is equal to: (1) $e$ (2) $0$ (3) $2$ (4) $2e$
Let $y(x)$ be the solution of the differential equation $(x \log x) \frac{dy}{dx} + y = 2x \log x$, $(x \geq 1)$. Then $y(e)$ is equal to:\\
(1) $e$\\
(2) $0$\\
(3) $2$\\
(4) $2e$