The integral $\int \frac{dx}{x^2(x^4+1)^{3/4}}$ equals:\\
(1) $-\left(1 + \frac{1}{x^4}\right)^{1/4} + C$\\
(2) $-\left(\frac{x^4+1}{x^4}\right)^{1/4} + C$\\
(3) $\left(\frac{x^4+1}{x^4}\right)^{1/4} + C$\\
(4) $\left(1 + \frac{1}{x^4}\right)^{1/4} + C$