If one of the diameters of the circle, given by the equation, $x^2 + y^2 - 4x + 6y - 12 = 0$, is a chord of a circle $S$, whose centre is at $(-3, 2)$, then the radius of $S$ is: (1) $5\sqrt{2}$ (2) $5\sqrt{3}$ (3) $5$ (4) $10$
If one of the diameters of the circle, given by the equation, $x^2 + y^2 - 4x + 6y - 12 = 0$, is a chord of a circle $S$, whose centre is at $(-3, 2)$, then the radius of $S$ is:\\
(1) $5\sqrt{2}$\\
(2) $5\sqrt{3}$\\
(3) $5$\\
(4) $10$