jee-main 2016 Q89

jee-main · India · 09apr First order differential equations (integrating factor)

The solution of the differential equation $\frac{dy}{dx} + \frac{y}{2}\sec^2 x = \frac{\tan x \sec^2 x}{2y}$, where $y(0) = 1$, is given by:
(1) $y^2 = 1 + \frac{\tan x}{x}$
(2) $y^2 = 1 + \tan x$
(3) $y = 1 - \tan x$
(4) $y^2 = 1 - \tan x$

The solution of the differential equation $\frac{dy}{dx} + \frac{y}{2}\sec^2 x = \frac{\tan x \sec^2 x}{2y}$, where $y(0) = 1$, is given by:\\
(1) $y^2 = 1 + \frac{\tan x}{x}$\\
(2) $y^2 = 1 + \tan x$\\
(3) $y = 1 - \tan x$\\
(4) $y^2 = 1 - \tan x$

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