jee-main 2020 Q56

jee-main · India · session2_04sep_shift1 Straight Lines & Coordinate Geometry Area Computation in Coordinate Geometry
A triangle $ABC$ lying in the first quadrant has two vertices as $A ( 1,2 )$ and $B ( 3,1 )$. If $\angle BAC = 90 ^ { \circ }$, and $\operatorname { ar } ( \Delta \mathrm { ABC } ) = 5 \sqrt { 5 }$ sq. units, then the abscissa of the vertex C is :
(1) $1 + \sqrt { 5 }$
(2) $1 + 2 \sqrt { 5 }$
(3) $2 + \sqrt { 5 }$
(4) $2 \sqrt { 5 } - 1$ 
A triangle $ABC$ lying in the first quadrant has two vertices as $A ( 1,2 )$ and $B ( 3,1 )$. If $\angle BAC = 90 ^ { \circ }$, and $\operatorname { ar } ( \Delta \mathrm { ABC } ) = 5 \sqrt { 5 }$ sq. units, then the abscissa of the vertex C is :\\
(1) $1 + \sqrt { 5 }$\\
(2) $1 + 2 \sqrt { 5 }$\\
(3) $2 + \sqrt { 5 }$\\
(4) $2 \sqrt { 5 } - 1$
Paper Questions
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