The area of the region bounded by $y ^ { 2 } = 8 x$ and $y ^ { 2 } = 16 ( 3 - x )$ is equal to\\ (1) $\frac { 32 } { 3 }$\\ (2) $\frac { 40 } { 3 }$\\ (3) 16\\ (4) 9