The sum $1 + 2 \cdot 3 + 3 \cdot 3^2 + \ldots + 10 \cdot 3^9$ is equal to\\ (1) $\frac{2 \cdot 3^{12} + 10}{4}$\\ (2) $\frac{19 \cdot 3^{10} + 1}{4}$\\ (3) $5 \cdot 3^{10} - 2$\\ (4) $\frac{9 \cdot 3^{10} + 1}{2}$