jee-main 2022 Q24

jee-main · India · session1_25jun_shift2 Not Maths
Moment of Inertia (M.I.) of four bodies having same mass $M$ and radius $2R$ are as follows $I_1 =$ M.I. of solid sphere about its diameter $I_2 =$ M.I. of solid cylinder about its axis $I_3 =$ M.I. of solid circular disc about its diameter $I_4 =$ M.I. of thin circular ring about its diameter If $2I_2 + I_3 + I_4 = xI_1$ then the value of $x$ will be $\_\_\_\_$.
Moment of Inertia (M.I.) of four bodies having same mass $M$ and radius $2R$ are as follows\\
$I_1 =$ M.I. of solid sphere about its diameter\\
$I_2 =$ M.I. of solid cylinder about its axis\\
$I_3 =$ M.I. of solid circular disc about its diameter\\
$I_4 =$ M.I. of thin circular ring about its diameter\\
If $2I_2 + I_3 + I_4 = xI_1$ then the value of $x$ will be $\_\_\_\_$.