If the system of equations $x + y + z = 6$ $2x + 5y + \alpha z = \beta$ $x + 2y + 3z = 14$ has infinitely many solutions, then $\alpha + \beta$ is equal to (1) 8 (2) 36 (3) 44 (4) 48
If the system of equations\\
$x + y + z = 6$\\
$2x + 5y + \alpha z = \beta$\\
$x + 2y + 3z = 14$\\
has infinitely many solutions, then $\alpha + \beta$ is equal to\\
(1) 8\\
(2) 36\\
(3) 44\\
(4) 48