The statement $(p \Rightarrow (q \vee p)) \Rightarrow r$ is NOT equivalent to:\\ (1) $p \wedge \sim r \Rightarrow q$\\ (2) $\sim q \Rightarrow (\sim r \vee p)$\\ (3) $p \Rightarrow (q \vee r)$\\ (4) $p \wedge \sim q \Rightarrow r$