As per the given figure, if $\frac{\mathrm{d}I}{\mathrm{d}t} = -1~\mathrm{A~s}^{-1}$, then the value of $V_{\mathrm{AB}}$ at this instant will be $\_\_\_\_$ V.
As per the given figure, if $\frac{\mathrm{d}I}{\mathrm{d}t} = -1~\mathrm{A~s}^{-1}$, then the value of $V_{\mathrm{AB}}$ at this instant will be $\_\_\_\_$ V.