Let $a \neq 0$. Let $G$ be a curve which is symmetric with respect to the origin $(0,0)$ to the graph of the quadratic function in $x$ $$y = ax^2 - 4x - 4a. \tag{1}$$ (1) The coordinates of the vertex of the graph of (1) are $$\left( \frac{\mathbf{A}}{a}, -\frac{\mathbf{B}}{a} - 4a \right).$$ (2) Among the following choices, the quadratic function whose graph is $G$ is $\square$ C. (0) $y = ax^2 + 4x + 4a$ (1) $y = ax^2 + 4x - 4a$ (2) $y = ax^2 - 4x + 4a$ (3) $y = -ax^2 + 4x + 4a$ (4) $y = -ax^2 - 4x + 4a$ (5) $y = -ax^2 - 4x - 4a$ (3) The curve $G$ intersects the graph of the quadratic function (1) at the two points $$(\mathrm{DE},\ \mathrm{F}) \text{ and } (\mathrm{G},\ \mathrm{HI}).$$ (4) Let $a = 2$. Then over the interval $\mathrm{DE} \leqq x \leqq \square\mathrm{G}$, the maximum and the minimum values of the quadratic function whose graph is $G$ are JK and LM, respectively.
Let $a \neq 0$. Let $G$ be a curve which is symmetric with respect to the origin $(0,0)$ to the graph of the quadratic function in $x$
$$y = ax^2 - 4x - 4a. \tag{1}$$
(1) The coordinates of the vertex of the graph of (1) are
$$\left( \frac{\mathbf{A}}{a}, -\frac{\mathbf{B}}{a} - 4a \right).$$
(2) Among the following choices, the quadratic function whose graph is $G$ is $\square$ C.\\
(0) $y = ax^2 + 4x + 4a$\\
(1) $y = ax^2 + 4x - 4a$\\
(2) $y = ax^2 - 4x + 4a$\\
(3) $y = -ax^2 + 4x + 4a$\\
(4) $y = -ax^2 - 4x + 4a$\\
(5) $y = -ax^2 - 4x - 4a$
(3) The curve $G$ intersects the graph of the quadratic function (1) at the two points
$$(\mathrm{DE},\ \mathrm{F}) \text{ and } (\mathrm{G},\ \mathrm{HI}).$$
(4) Let $a = 2$. Then over the interval $\mathrm{DE} \leqq x \leqq \square\mathrm{G}$, the maximum and the minimum values of the quadratic function whose graph is $G$ are JK and LM, respectively.