taiwan-gsat 2024 Q5

taiwan-gsat · Other · gsat__math-a 5 marks Combinations & Selection Selection with Group/Category Constraints

Divide the 50 positive integers from 1 to 50 equally into groups A and B, with 25 numbers in each group, such that the median of group A is 1 less than the median of group B. How many ways are there to divide them?
(1) $C_{25}^{50}$
(2) $C_{24}^{48}$
(3) $C_{12}^{24}$
(4) $\left(C_{12}^{24}\right)^{2}$
(5) $C_{24}^{48} \cdot C_{12}^{24}$

Divide the 50 positive integers from 1 to 50 equally into groups A and B, with 25 numbers in each group, such that the median of group A is 1 less than the median of group B. How many ways are there to divide them?\\
(1) $C_{25}^{50}$\\
(2) $C_{24}^{48}$\\
(3) $C_{12}^{24}$\\
(4) $\left(C_{12}^{24}\right)^{2}$\\
(5) $C_{24}^{48} \cdot C_{12}^{24}$

Paper Questions

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