There are two fair six-sided dice A and B:\\
The numbers on A are $1, 2, 5, 6, 7, 9$,\\
The numbers on B are $1, 3, 4, 5, 6, 9$.\\
The relationship between the numbers on A and B is recorded in the table below. For example: if the numbers on A and B are 5 and 3 respectively, it is recorded as ``A wins''; if both A and B show 5, it is recorded as ``tie''.

\begin{center}
\begin{tabular}{|l|l|l|l|l|l|l|l|}
\hline
\multirow{2}{*}{} &  & \multicolumn{6}{|c|}{A} \\
\hline
 & Number & 1 & 2 & 5 & 6 & 7 & 9 \\
\hline
\multirow{6}{*}{B} & 1 & Tie & A wins & A wins & A wins & A wins & A wins \\
\hline
 & 3 & B wins & B wins & A wins & A wins & A wins & A wins \\
\hline
 & 4 & B wins & B wins & A wins & A wins & A wins & A wins \\
\hline
 & 5 & B wins & B wins & Tie & A wins & A wins & A wins \\
\hline
 & 6 & B wins & B wins & B wins & Tie & A wins & A wins \\
\hline
 & 9 & B wins & B wins & B wins & B wins & B wins & Tie \\
\hline
\end{tabular}
\end{center}

If a person rolls both dice A and B simultaneously, what is the probability that B shows 6 given that A's number is greater than B's number?\\
(1) $\frac { 1 } { 6 }$\\
(2) $\frac { 1 } { 9 }$\\
(3) $\frac { 1 } { 16 }$\\
(4) $\frac { 1 } { 18 }$\\
(5) $\frac { 1 } { 32 }$