The obtaining of ethanol using sugarcane involves the fermentation of monosaccharides that form the sucrose contained in molasses. One of these formers is glucose $\left(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\right)$, whose fermentation produces about 50 g of ethanol from 100 g of glucose, according to the chemical equation described.
Under a specific fermentation condition, 80\% conversion to ethanol is obtained which, after its purification, presents a density equal to $0.80 \mathrm{~g/mL}$. The molasses used contained 50 kg of monosaccharides in the form of glucose.
The volume of ethanol, in liters, obtained in this process is closest to
(A) 16.
(B) 20.
(C) 25.
(D) 64.
(E) 100.