Set $S$ has $1 \times 2$ matrices as elements and set $T$ has $2 \times 1$ matrices as elements, as follows. $$S = \{ ( a \; b ) \mid a + b \neq 0 \} , \quad T = \left\{ \left. \binom { p } { q } \right\rvert \, p q \neq 0 \right\}$$ Which of the following are correct for element $A$ of set $S$? Choose all that apply from $\langle$Remarks$\rangle$. [4 points] $\langle$Remarks$\rangle$ ㄱ. For element $P$ of set $T$, $PA$ does not have an inverse matrix. ㄴ. For element $B$ of set $S$ and element $P$ of set $T$, if $PA = PB$ then $A = B$. ㄷ. Among the elements of set $T$, there exists $P$ satisfying $PA \binom { 1 } { 1 } = \binom { 1 } { 1 }$. (1) ㄱ (2) ㄷ (3) ㄱ, ㄴ (4) ㄴ, ㄷ (5) ㄱ, ㄴ, ㄷ
Set $S$ has $1 \times 2$ matrices as elements and set $T$ has $2 \times 1$ matrices as elements, as follows.
$$S = \{ ( a \; b ) \mid a + b \neq 0 \} , \quad T = \left\{ \left. \binom { p } { q } \right\rvert \, p q \neq 0 \right\}$$
Which of the following are correct for element $A$ of set $S$? Choose all that apply from $\langle$Remarks$\rangle$. [4 points]
$\langle$Remarks$\rangle$\\
ㄱ. For element $P$ of set $T$, $PA$ does not have an inverse matrix.\\
ㄴ. For element $B$ of set $S$ and element $P$ of set $T$, if $PA = PB$ then $A = B$.\\
ㄷ. Among the elements of set $T$, there exists $P$ satisfying $PA \binom { 1 } { 1 } = \binom { 1 } { 1 }$.\\
(1) ㄱ\\
(2) ㄷ\\
(3) ㄱ, ㄴ\\
(4) ㄴ, ㄷ\\
(5) ㄱ, ㄴ, ㄷ