csat-suneung 2011 Q27 (Calculus)

csat-suneung · South-Korea · csat__math-science 3 marks Implicit equations and differentiation Compute slope at a point via implicit differentiation (single-step)
On the coordinate plane, what is the slope of the tangent line to the curve $y ^ { 3 } = \ln \left( 5 - x ^ { 2 } \right) + x y + 4$ at the point $( 2,2 )$? [3 points]
(1) $- \frac { 3 } { 5 }$
(2) $- \frac { 1 } { 2 }$
(3) $- \frac { 2 } { 5 }$
(4) $- \frac { 3 } { 10 }$
(5) $- \frac { 1 } { 5 }$
On the coordinate plane, what is the slope of the tangent line to the curve $y ^ { 3 } = \ln \left( 5 - x ^ { 2 } \right) + x y + 4$ at the point $( 2,2 )$? [3 points]\\
(1) $- \frac { 3 } { 5 }$\\
(2) $- \frac { 1 } { 2 }$\\
(3) $- \frac { 2 } { 5 }$\\
(4) $- \frac { 3 } { 10 }$\\
(5) $- \frac { 1 } { 5 }$