On the coordinate plane, what is the slope of the tangent line to the curve $y ^ { 3 } = \ln \left( 5 - x ^ { 2 } \right) + x y + 4$ at the point $( 2,2 )$? [3 points]\\
(1) $- \frac { 3 } { 5 }$\\
(2) $- \frac { 1 } { 2 }$\\
(3) $- \frac { 2 } { 5 }$\\
(4) $- \frac { 3 } { 10 }$\\
(5) $- \frac { 1 } { 5 }$