As shown in the figure, for a tetrahedron ABCD with $\overline{\mathrm{AB}} = 6$, $\overline{\mathrm{BC}} = 4\sqrt{5}$, let M be the midpoint of segment BC. Triangle AMD is equilateral and line BC is perpendicular to plane AMD. Find the area of the orthogonal projection of the circle inscribed in triangle ACD onto plane BCD. [3 points]\\
(1) $\frac{\sqrt{10}}{4}\pi$\\
(2) $\frac{\sqrt{10}}{6}\pi$\\
(3) $\frac{\sqrt{10}}{8}\pi$\\
(4) $\frac{\sqrt{10}}{10}\pi$\\
(5) $\frac{\sqrt{10}}{12}\pi$