LFM Pure

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Let $P S$ be the median of the triangle with vertices $P ( 2,2 ) , Q ( 6 , - 1 )$ and $R ( 7,3 )$. The equation of the line passing through $( 1 , - 1 )$ and parallel to $P S$ is
(1) $4 x + 7 y + 3 = 0$
(2) $2 x - 9 y - 11 = 0$
(3) $4 x - 7 y - 11 = 0$
(4) $2 x + 9 y + 7 = 0$
The circumcentre of a triangle lies at the origin and its centroid is the midpoint of the line segment joining the points $\left( a ^ { 2 } + 1 , a ^ { 2 } + 1 \right)$ and $( 2 a , - 2 a ) , a \neq 0$. Then for any $a$, the orthocentre of this triangle lies on the line
(1) $y - \left( a ^ { 2 } + 1 \right) x = 0$
(2) $y - 2 a x = 0$
(3) $y + x = 0$
(4) $( a - 1 ) ^ { 2 } x - ( a + 1 ) ^ { 2 } y = 0$
jee-main 2014 Q69 Collinearity and Concurrency View
Let $a , b , c$ and $d$ be non-zero numbers. If the point of intersection of the lines $4 a x + 2 a y + c = 0$ \& $5 b x + 2 b y + d = 0$ lies in the fourth quadrant and is equidistant from the two axes then
(1) $3 b c - 2 a d = 0$
(2) $3 b c + 2 a d = 0$
(3) $2 b c - 3 a d = 0$
(4) $2 b c + 3 a d = 0$
Given three points $P , Q , R$ with $P ( 5,3 )$ and $R$ lies on the $x$-axis. If the equation of $RQ$ is $x - 2 y = 2$ and $PQ$ is parallel to the $x$-axis, then the centroid of $\triangle PQR$ lies on the line
(1) $x - 2 y + 1 = 0$
(2) $2 x + y - 9 = 0$
(3) $2 x - 5 y = 0$
(4) $5 x - 2 y = 0$
jee-main 2015 Q69 Locus Determination View
Locus of the image of the point $( 2,3 )$ in the line $( 2 x - 3 y + 4 ) + k ( x - 2 y + 3 ) = 0 , k \in \mathbb{R}$, is a
(1) Circle of radius $\sqrt { 3 }$
(2) Straight line parallel to $x$-axis.
(3) Straight line parallel to $y$-axis.
(4) Circle of radius $\sqrt { 2 }$
A straight line through origin $O$ meets the lines $3y = 10 - 4x$ and $8x + 6y + 5 = 0$ at points $A$ and $B$ respectively. Then $O$ divides the segment $AB$ in the ratio: (1) $2:3$ (2) $1:2$ (3) $4:1$ (4) $3:4$
A straight line through origin $O$ meets the lines $3 y = 10 - 4 x$ and $8 x + 6 y + 5 = 0$ at points $A$ and $B$ respectively. Then, $O$ divides the segment $A B$ in the ratio
(1) $2 : 3$
(2) $1 : 2$
(3) $4 : 1$
(4) $3 : 4$
jee-main 2016 Q70 Reflection and Image in a Line View
A ray of light is incident along a line which meets another line $7 x - y + 1 = 0$ at the point $( 0,1 )$. The ray is then reflected from this point along the line $y + 2 x = 1$. Then the equation of the line of incidence of the ray of light is :
(1) $41 x - 25 y + 25 = 0$
(2) $41 x + 25 y - 25 = 0$
(3) $41 x - 38 y + 38 = 0$
(4) $41 x + 38 y - 38 = 0$
Two sides of a rhombus are along the lines, $x - y + 1 = 0$ and $7x - y - 5 = 0$. If its diagonals intersect at $(-1, -2)$, then which one of the following is a vertex of this rhombus?
(1) $(-3, -9)$
(2) $(-3, -8)$
(3) $\left(\frac{1}{3}, -\frac{8}{3}\right)$
(4) $\left(-\frac{1}{3}, -\frac{8}{3}\right)$
Let $k$ be an integer such that the triangle with vertices $(k, -3)$, $(5, k)$ and $(-k, 2)$ has area 28 sq. units. Then the orthocenter of this triangle is at the point:
(1) $\left(2, -\dfrac{1}{2}\right)$
(2) $\left(1, \dfrac{3}{4}\right)$
(3) $\left(1, -\dfrac{3}{4}\right)$
(4) $\left(2, \dfrac{1}{2}\right)$
jee-main 2017 Q75 Locus Determination View
If a variable line drawn through the intersection of the lines $\frac { x } { 3 } + \frac { y } { 4 } = 1$ and $\frac { x } { 4 } + \frac { y } { 3 } = 1$, meets the coordinate axes at $A$ and $B$, $( A \neq B )$, then the locus of the midpoint of $AB$ is:
(1) $7 x y = 6 ( x + y )$
(2) $4 ( x + y ) ^ { 2 } - 28 ( x + y ) + 49 = 0$
(3) $6 x y = 7 ( x + y )$
(4) $14 ( x + y ) ^ { 2 } - 97 ( x + y ) + 168 = 0$
jee-main 2018 Q68 Locus Determination View
A straight line through a fixed point $( 2,3 )$ intersects the coordinate axes at distinct points $P$ and $Q$. If $O$ is the origin and the rectangle $O P R Q$ is completed, then the locus of $R$ is:
(1) $3 x + 2 y = 6 x y$
(2) $3 x + 2 y = 6$
(3) $2 x + 3 y = x y$
(4) $3 x + 2 y = x y$
In a triangle $A B C$, coordiantates of $A$ are $( 1,2 )$ and the equations of the medians through $B$ and $C$ are $x + y = 5$ and $x = 4$ respectively. Then area of $\triangle A B C$ (in sq. units) is
(1) 5
(2) 9
(3) 12
(4) 4
In a triangle $ABC$, coordinates of $A$ are $(1,2)$ and the equations of the medians through $B$ and $C$ are respectively, $x + y = 5$ and $x = 4$. Then area of $\triangle ABC$ (in sq. units) is :
(1) 12
(2) 4
(3) 9
(4) 5
Let the orthocentre and centroid of a triangle be $A ( - 3,5 )$ and $B ( 3,3 )$ respectively. If $C$ is the circumcentre of this triangle, then the radius of the circle having line segment $A C$ as diameter, is:
(1) $\frac { 3 \sqrt { } 5 } { 2 }$
(2) $\sqrt { 10 }$
(3) $2 \sqrt { 10 }$
(4) $3 \sqrt { \frac { 5 } { 2 } }$
Two vertices of a triangle are $( 0,2 )$ and $( 4,3 )$. If its orthocenter is at the origin, then its third vertex lies in which quadrant?
jee-main 2019 Q67 Slope and Angle Between Lines View
Suppose that the points $( h , k )$, $( 1,2 )$ and $( - 3,4 )$ lie on the line $L _ { 1 }$. If a line $L _ { 2 }$ passing through the points $( h , k )$ and $( 4,3 )$ is perpendicular to $L _ { 1 }$, then $\frac { k } { h }$ equals:
(1) $- \frac { 1 } { 7 }$
(2) 3
(3) 0
(4) $\frac { 1 } { 3 }$
If the line $3 x + 4 y - 24 = 0$ intersects the $x$-axis is at the point $A$ and the $y$-axis at the point $B$, then the incentre of the triangle $O A B$, where $O$ is the origin, is:
(1) $( 4,4 )$
(2) $( 3,4 )$
(3) $( 4,3 )$
(4) $( 2,2 )$
If a straight line passing through the point $P ( - 3,4 )$ is such that its intercepted portion between the coordinate axes is bisected at $P$, then its equation is :
(1) $4 x + 3 y = 0$
(2) $4 x - 3 y + 24 = 0$
(3) $3 x - 4 y + 25 = 0$
(4) $x - y + 7 = 0$
A point on the straight line, $3x + 5y = 15$ which is equidistant from the coordinate axes will lie only in:
(1) $1^{\text{st}}$ and $2^{\text{nd}}$ quadrants
(2) $1^{\text{st}}$, $2^{\text{nd}}$ and $4^{\text{th}}$ quadrants
(3) $1^{\text{st}}$ quadrant
(4) $4^{\text{th}}$ quadrant
jee-main 2019 Q68 Slope and Angle Between Lines View
Slope of a line passing through $P ( 2,3 )$ and intersecting the line $x + y = 7$ at a distance of 4 units from $P$, is
(1) $\frac { \sqrt { 7 } - 1 } { \sqrt { 7 } + 1 }$
(2) $\frac { 1 - \sqrt { 7 } } { 1 + \sqrt { 7 } }$
(3) $\frac { \sqrt { 5 } - 1 } { \sqrt { 5 } + 1 }$
(4) $\frac { 1 - \sqrt { 5 } } { 1 + \sqrt { 5 } }$
If the two lines $x + ( a - 1 ) y = 1$ and $2 x + a ^ { 2 } y = 1 , ( a \in R - \{ 0,1 \} )$ are perpendicular, then the distance of their point of intersection from the origin is
(1) $\frac { 2 } { \sqrt { 5 } }$
(2) $\frac { \sqrt { 2 } } { 5 }$
(3) $\frac { 2 } { 5 }$
(4) $\sqrt { \frac { 2 } { 5 } }$
jee-main 2019 Q69 Locus Determination View
A point $P$ moves on the line $2 x - 3 y + 4 = 0$. If $Q ( 1,4 )$ and $R ( 3 , - 2 )$ are fixed points, then the locus of the centroid of $\triangle P Q R$ is a line:
(1) with slope $\frac { 2 } { 3 }$
(2) with slope $\frac { 3 } { 2 }$
(3) parallel to $y$-axis
(4) parallel to $x$-axis
Let the equations of two sides of a triangle be $3x - 2y + 6 = 0$ and $4x + 5y - 20 = 0$. If the orthocenter of this triangle is at $(1,1)$ then the equation of its third side is:
(1) $122y + 26x + 1675 = 0$
(2) $26x - 122y - 1675 = 0$
(3) $26x + 61y + 1675 = 0$
(4) $122y - 26x - 1675 = 0$
Two vertical poles of height, $20 m$ and $80 m$ stand apart on a horizontal plane. The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other, from this horizontal plane is:
(1) 16
(2) 12
(3) 18
(4) 15