A straight line through origin $O$ meets the lines $3 y = 10 - 4 x$ and $8 x + 6 y + 5 = 0$ at points $A$ and $B$ respectively. Then, $O$ divides the segment $A B$ in the ratio (1) $2 : 3$ (2) $1 : 2$ (3) $4 : 1$ (4) $3 : 4$
A straight line through origin $O$ meets the lines $3 y = 10 - 4 x$ and $8 x + 6 y + 5 = 0$ at points $A$ and $B$ respectively. Then, $O$ divides the segment $A B$ in the ratio\\
(1) $2 : 3$\\
(2) $1 : 2$\\
(3) $4 : 1$\\
(4) $3 : 4$