jee-main 2016 Q61

jee-main · India · 10apr Indices and Surds Solving Equations Involving Surds

If $x$ is a solution of the equation $\sqrt { 2 x + 1 } - \sqrt { 2 x - 1 } = 1 , \left( x \geq \frac { 1 } { 2 } \right)$, then $\sqrt { 4 x ^ { 2 } - 1 }$ is equal to :
(1) $\frac { 3 } { 4 }$
(2) $\frac { 1 } { 2 }$
(3) $2 \sqrt { 2 }$
(4) 2

If $x$ is a solution of the equation $\sqrt { 2 x + 1 } - \sqrt { 2 x - 1 } = 1 , \left( x \geq \frac { 1 } { 2 } \right)$, then $\sqrt { 4 x ^ { 2 } - 1 }$ is equal to :\\
(1) $\frac { 3 } { 4 }$\\
(2) $\frac { 1 } { 2 }$\\
(3) $2 \sqrt { 2 }$\\
(4) 2

Paper Questions

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