Let $k$ be an integer such that the triangle with vertices $(k, -3)$, $(5, k)$ and $(-k, 2)$ has area 28 sq. units. Then the orthocenter of this triangle is at the point:
(1) $\left(2, -\dfrac{1}{2}\right)$
(2) $\left(1, \dfrac{3}{4}\right)$
(3) $\left(1, -\dfrac{3}{4}\right)$
(4) $\left(2, \dfrac{1}{2}\right)$
Let $k$ be an integer such that the triangle with vertices $(k, -3)$, $(5, k)$ and $(-k, 2)$ has area 28 sq. units. Then the orthocenter of this triangle is at the point:\\
(1) $\left(2, -\dfrac{1}{2}\right)$\\
(2) $\left(1, \dfrac{3}{4}\right)$\\
(3) $\left(1, -\dfrac{3}{4}\right)$\\
(4) $\left(2, \dfrac{1}{2}\right)$