If, for a positive integer $n$, the quadratic equation,
$$x(x + 1) + (x + 1)(x + 2) + \ldots + (x + \overline{n-1})(x + n) = 10n$$
has two consecutive integral solutions, then $n$ is equal to:
(1) 12
(2) 9
(3) 10
(4) 11
If, for a positive integer $n$, the quadratic equation,

$$x(x + 1) + (x + 1)(x + 2) + \ldots + (x + \overline{n-1})(x + n) = 10n$$

has two consecutive integral solutions, then $n$ is equal to:\\
(1) 12\\
(2) 9\\
(3) 10\\
(4) 11