If, for a positive integer $n$, the quadratic equation, $$x(x + 1) + (x + 1)(x + 2) + \ldots + (x + \overline{n-1})(x + n) = 10n$$ has two consecutive integral solutions, then $n$ is equal to:\\ (1) 12\\ (2) 9\\ (3) 10\\ (4) 11