Consider the lines
$$\begin{aligned}
& L _ { 1 } : \frac { x + 1 } { 3 } = \frac { y + 2 } { 1 } = \frac { z + 1 } { 2 } \\
& L _ { 2 } : \frac { x - 2 } { 1 } = \frac { y + 2 } { 2 } = \frac { z - 3 } { 3 }
\end{aligned}$$
The shortest distance between $L _ { 1 }$ and $L _ { 2 }$ is\\
(A) 0\\
(B) $\frac { 17 } { \sqrt { 3 } }$\\
(C) $\frac { 41 } { 5 \sqrt { 3 } }$\\
(D) $\frac { 17 } { 5 \sqrt { 3 } }$