jee-main 2018 Q10

jee-main · India · 15apr_shift2 Not Maths
A body takes 10 minutes to cool from $60 ^ { \circ } \mathrm { C }$ to $50 ^ { \circ } \mathrm { C }$. The temperature of surroundings is constant at $25 ^ { \circ } \mathrm { C }$. Then, the temperature of the body after next 10 minutes will be approximately
(1) $43 ^ { \circ } \mathrm { C }$
(2) $47 ^ { \circ } \mathrm { C }$
(3) $41 ^ { \circ } \mathrm { C }$
(4) $45 ^ { \circ } \mathrm { C }$
A body takes 10 minutes to cool from $60 ^ { \circ } \mathrm { C }$ to $50 ^ { \circ } \mathrm { C }$. The temperature of surroundings is constant at $25 ^ { \circ } \mathrm { C }$. Then, the temperature of the body after next 10 minutes will be approximately\\
(1) $43 ^ { \circ } \mathrm { C }$\\
(2) $47 ^ { \circ } \mathrm { C }$\\
(3) $41 ^ { \circ } \mathrm { C }$\\
(4) $45 ^ { \circ } \mathrm { C }$