jee-main 2018 Q48

jee-main · India · 15apr_shift2 Not Maths
Two 5 molal solutions are prepared by dissolving a non-electrolyte, non-volatile solute separately in the solvents X and Y . The molecular weights of the solvents are $\mathrm { M } _ { \mathrm { X } }$ and $\mathrm { M } _ { \mathrm { Y } }$, respectively where $\mathrm { M } _ { X } = \frac { 3 } { 4 } \mathrm { M } _ { \mathrm { Y } }$. The relative lowering of vapour pressure of the solution in X is "m" times that of the solution in Y . Given that the number of moles of solute is very small in comparison to that of solvent, the value of "m" is:
(1) $\frac { 3 } { 4 }$
(2) $\frac { 1 } { 2 }$
(3) $\frac { 1 } { 4 }$
(4) $\frac { 4 } { 3 }$
Two 5 molal solutions are prepared by dissolving a non-electrolyte, non-volatile solute separately in the solvents X and Y . The molecular weights of the solvents are $\mathrm { M } _ { \mathrm { X } }$ and $\mathrm { M } _ { \mathrm { Y } }$, respectively where $\mathrm { M } _ { X } = \frac { 3 } { 4 } \mathrm { M } _ { \mathrm { Y } }$. The relative lowering of vapour pressure of the solution in X is "m" times that of the solution in Y . Given that the number of moles of solute is very small in comparison to that of solvent, the value of "m" is:\\
(1) $\frac { 3 } { 4 }$\\
(2) $\frac { 1 } { 2 }$\\
(3) $\frac { 1 } { 4 }$\\
(4) $\frac { 4 } { 3 }$