The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):\\
(1) $\frac { \pi } { 6 }$\\
(2) $\frac { \pi } { 3 }$\\
(3) $\frac { \pi } { 8 }$\\
(4) $\frac { \pi } { 4 }$