jee-main 2019 Q13

jee-main · India · session1_11jan_shift2 Simple Harmonic Motion
A pendulum is executing simple harmonic motion and its maximum kinetic energy is $\mathrm { K } _ { 1 }$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is $\mathrm { K } _ { 2 }$
(1) $K _ { 2 } = 2 K _ { 1 }$
(2) $\mathrm { K } _ { 2 } = \frac { \mathrm { K } _ { 1 } } { 2 }$
(3) $K _ { 2 } = \frac { K _ { 1 } } { 4 }$
(4) $K _ { 2 } = K$
A pendulum is executing simple harmonic motion and its maximum kinetic energy is $\mathrm { K } _ { 1 }$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is $\mathrm { K } _ { 2 }$\\
(1) $K _ { 2 } = 2 K _ { 1 }$\\
(2) $\mathrm { K } _ { 2 } = \frac { \mathrm { K } _ { 1 } } { 2 }$\\
(3) $K _ { 2 } = \frac { K _ { 1 } } { 4 }$\\
(4) $K _ { 2 } = K$