jee-main 2019 Q26

jee-main · India · session1_11jan_shift2 Not Maths

In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm. The decrease in the stopping potential is close to: $\left( \frac { \mathrm { hc } } { \mathrm { e } } = 1240 \mathrm {~nm} - \mathrm { V } \right)$
(1) 0.5 V
(2) 1.5 V
(3) 1.0 V
(4) 2.0 V

In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm. The decrease in the stopping potential is close to: $\left( \frac { \mathrm { hc } } { \mathrm { e } } = 1240 \mathrm {~nm} - \mathrm { V } \right)$\\
(1) 0.5 V\\
(2) 1.5 V\\
(3) 1.0 V\\
(4) 2.0 V

Paper Questions

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