jee-main 2019 Q1

jee-main · India · session2_10apr_shift1 Not Maths
A particle of mass $m$ is moving along a trajectory given by $x = x _ { 0 } + \mathrm { a } \cos \omega _ { 1 } \mathrm { t }$ $y = y _ { 0 } + \mathrm { b } \sin \omega _ { 2 } \mathrm { t }$ The torque, acting on the particle about the origin, at $\mathrm { t } = 0$ is:
(1) $+ \mathrm { m } y _ { 0 } \mathrm { a } \omega _ { 1 } ^ { 2 } \widehat { \mathrm { k } }$
(2) $- \mathrm { m } \left( x _ { 0 } \mathrm {~b} \omega _ { 2 } ^ { 2 } - y _ { 0 } \mathrm { a } \omega _ { 1 } ^ { 2 } \right) \widehat { \mathrm { k } }$
(3) Zero
(4) $\mathrm { m } \left( - x _ { 0 } \mathrm {~b} + y _ { 0 } \mathrm { a } \right) \omega _ { 1 } ^ { 2 } \widehat { \mathrm { k } }$
A particle of mass $m$ is moving along a trajectory given by\\
$x = x _ { 0 } + \mathrm { a } \cos \omega _ { 1 } \mathrm { t }$\\
$y = y _ { 0 } + \mathrm { b } \sin \omega _ { 2 } \mathrm { t }$\\
The torque, acting on the particle about the origin, at $\mathrm { t } = 0$ is:\\
(1) $+ \mathrm { m } y _ { 0 } \mathrm { a } \omega _ { 1 } ^ { 2 } \widehat { \mathrm { k } }$\\
(2) $- \mathrm { m } \left( x _ { 0 } \mathrm {~b} \omega _ { 2 } ^ { 2 } - y _ { 0 } \mathrm { a } \omega _ { 1 } ^ { 2 } \right) \widehat { \mathrm { k } }$\\
(3) Zero\\
(4) $\mathrm { m } \left( - x _ { 0 } \mathrm {~b} + y _ { 0 } \mathrm { a } \right) \omega _ { 1 } ^ { 2 } \widehat { \mathrm { k } }$