At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea $= 60 \mathrm {~g} \mathrm {~mol} ^ { - 1 }$)\\
(1) 0.028 mm Hg\\
(2) 0.027 mm Hg\\
(3) 0.031 mm Hg\\
(4) 0.017 mm Hg