jee-main 2019 Q5

jee-main · India · session2_10apr_shift2 Not Maths
A solid sphere of mass $M$ and radius $R$ is divided into two unequal parts. The first part has a mass of $\frac { 7M } { 8 }$ and is converted into uniform disc of radius $2R$. The second part is converted into a uniform solid sphere. Let $I _ { 1 }$ be the moment of inertia of the disc about its axis and $\mathrm { I } _ { 2 }$ be the moment of inertia of the new sphere about its axis. The ratio $I _ { 1 } / I _ { 2 }$ is given by:
(1) 140
(2) 185
(3) 65
(4) 285
A solid sphere of mass $M$ and radius $R$ is divided into two unequal parts. The first part has a mass of $\frac { 7M } { 8 }$ and is converted into uniform disc of radius $2R$. The second part is converted into a uniform solid sphere. Let $I _ { 1 }$ be the moment of inertia of the disc about its axis and $\mathrm { I } _ { 2 }$ be the moment of inertia of the new sphere about its axis. The ratio $I _ { 1 } / I _ { 2 }$ is given by:\\
(1) 140\\
(2) 185\\
(3) 65\\
(4) 285