jee-main 2019 Q12

jee-main · India · session2_10apr_shift2 Not Maths
Water from a tap emerges vertically downwards with an initial speed of $1.0 \mathrm {~ms} ^ { - 1 }$. The cross-sectional area of the tap is $10 ^ { - 4 } \mathrm {~m} ^ { 2 }$. Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross-sectional area of the stream, 0.15 m below the tap would be: (Take $\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 }$ )
(1) $1 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$
(2) $5 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 }$
(3) $2 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$
(4) $5 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$
Water from a tap emerges vertically downwards with an initial speed of $1.0 \mathrm {~ms} ^ { - 1 }$. The cross-sectional area of the tap is $10 ^ { - 4 } \mathrm {~m} ^ { 2 }$. Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross-sectional area of the stream, 0.15 m below the tap would be:\\
(Take $\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 }$ )\\
(1) $1 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$\\
(2) $5 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 }$\\
(3) $2 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$\\
(4) $5 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$