The sum of the prime divisors of a natural number A is;
\begin{itemize}
\item 3 less than the sum of the prime divisors of $12 \cdot A$.
\item 5 less than the sum of the prime divisors of $70 \cdot A$.
\end{itemize}
Accordingly, what is the sum of the digits of the smallest value that A can take?\\
A) 4\\
B) 5\\
C) 6\\
D) 7\\
E) 8