9. Electrons with de-Broglie wavelength $\lambda$ fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is\\
(A) $\lambda _ { 0 } = \frac { 2 m c \lambda ^ { 2 } } { h }$\\
(B) $\quad \lambda _ { 0 } = \frac { 2 h } { m c }$\\
(C) $\lambda _ { 0 } = \frac { 2 m ^ { 2 } c ^ { 2 } \lambda ^ { 3 } } { h ^ { 2 } }$\\
(D) $\lambda _ { 0 } = \lambda$\\
Answer\\
D\\
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(A)\\
(B)\\
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(D)\\