14. The final solution contains\\
(A) $\left[ \mathrm { Pb } \left( \mathrm { NH } _ { 3 } \right) _ { 4 } \right] ^ { 2 + }$ and $\left[ \mathrm { CoCl } _ { 4 } \right] ^ { 2 - }$\\
(B) $\left[ \mathrm { Al } \left( \mathrm { NH } _ { 3 } \right) _ { 4 } \right] ^ { 3 + }$ and $\left[ \mathrm { Cu } \left( \mathrm { NH } _ { 3 } \right) _ { 4 } \right] ^ { 2 + }$\\
(C) $\left[ \mathrm { Ag } \left( \mathrm { NH } _ { 3 } \right) _ { 2 } \right] ^ { + }$and $\left[ \mathrm { Cu } \left( \mathrm { NH } _ { 3 } \right) _ { 4 } \right] ^ { 2 + }$\\
(D) $\left[ \mathrm { Ag } \left( \mathrm { NH } _ { 3 } \right) _ { 2 } \right] ^ { + }$and $\left[ \mathrm { Ni } \left( \mathrm { NH } _ { 3 } \right) _ { 6 } \right] ^ { 2 + }$

\section*{ANSWER: C}
\section*{Paragraph for Question Nos. 15 and 16}
An acyclic hydrocarbon $\mathbf { P }$, having molecular formula $\mathrm { C } _ { 6 } \mathrm { H } _ { 10 }$, gave acetone as the only organic product through the following sequence of reactions, in which $\mathbf { Q }$ is an intermediate organic compound.\\
(i) conc. $\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$ (catalytic amount)\\
$\left( \mathrm { C } _ { 6 } \mathrm { H } _ { 10 } \right)$\\
\includegraphics[max width=\textwidth, alt={}, center]{cdfce4af-7f3d-4d66-ab09-7da7ecb927ff-07_203_489_662_470}\\
\includegraphics[max width=\textwidth, alt={}, center]{cdfce4af-7f3d-4d66-ab09-7da7ecb927ff-07_157_466_684_1048}\\
\includegraphics[max width=\textwidth, alt={}, center]{cdfce4af-7f3d-4d66-ab09-7da7ecb927ff-07_187_912_686_967}\\
(ii) $\mathrm { NaBH } _ { 4 }$ /ethanol\\
(iii) dil. acid\\
(ii) $\mathrm { O } _ { 3 }$\\
(iii) $\mathrm { Zn } / \mathrm { H } _ { 2 } \mathrm { O }$\\