jee-main 2015 Q73

jee-main · India · 04apr Sign Change & Interval Methods

$\lim _ { x \rightarrow 0 } \frac { ( 1 - \cos 2 x ) ( 3 + \cos x ) } { x \tan 4 x } =$
(1) $\frac { 1 } { 2 }$
(2) 4
(3) 3
(4) 2

$\lim _ { x \rightarrow 0 } \frac { ( 1 - \cos 2 x ) ( 3 + \cos x ) } { x \tan 4 x } =$\\
(1) $\frac { 1 } { 2 }$\\
(2) 4\\
(3) 3\\
(4) 2