If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is
(1) $22 \left( \frac { 1 } { 3 } \right) ^ { 11 }$
(2) $\frac { 5 } { 19 }$
(3) $55 \left( \frac { 2 } { 3 } \right) ^ { 10 }$
(4) $220 \left( \frac { 1 } { 3 } \right) ^ { 12 }$
If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is\\
(1) $22 \left( \frac { 1 } { 3 } \right) ^ { 11 }$\\
(2) $\frac { 5 } { 19 }$\\
(3) $55 \left( \frac { 2 } { 3 } \right) ^ { 10 }$\\
(4) $220 \left( \frac { 1 } { 3 } \right) ^ { 12 }$