jee-main 2018 Q68

jee-main · India · 15apr Circles Circle Equation Derivation
A circle passes through the points $( 2,3 )$ and $( 4,5 )$. If its centre lies on the line $y - 4 x + 3 = 0$, then its radius is equal to :
(1) $\sqrt { 5 }$
(2) $\sqrt { 2 }$
(3) 2
(4) 1
A circle passes through the points $( 2,3 )$ and $( 4,5 )$. If its centre lies on the line $y - 4 x + 3 = 0$, then its radius is equal to :\\
(1) $\sqrt { 5 }$\\
(2) $\sqrt { 2 }$\\
(3) 2\\
(4) 1