jee-main 2018 Q90

jee-main · India · 15apr Conditional Probability Bayes' Theorem with Production/Source Identification

A box $A$ contains 2 white, 3 red and 2 black balls. Another box $B$ contains 4 white, 2 red and 3 black balls. If two balls are drawn at random, without replacement from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability that both balls are drawn from box $B$ is :
(1) $\frac { 7 } { 8 }$
(2) $\frac { 9 } { 16 }$
(3) $\frac { 7 } { 16 }$
(4) $\frac { 9 } { 32 }$

A box $A$ contains 2 white, 3 red and 2 black balls. Another box $B$ contains 4 white, 2 red and 3 black balls. If two balls are drawn at random, without replacement from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability that both balls are drawn from box $B$ is :\\
(1) $\frac { 7 } { 8 }$\\
(2) $\frac { 9 } { 16 }$\\
(3) $\frac { 7 } { 16 }$\\
(4) $\frac { 9 } { 32 }$

Paper Questions

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