jee-main 2018 Q83

jee-main · India · 15apr Integration by Substitution Substitution to Transform Integral Form (Show Transformed Expression)

If $f \left( \frac { x - 4 } { x + 2 } \right) = 2 x + 1 , ( x \in R - \{ 1 , - 2 \} )$, then $\int f ( x ) d x$ is equal to
(1) $12 \ln | 1 - x | - 3 x + C$
(2) $- 12 \ln | 1 - x | - 3 x + C$
(3) $12 \ln | 1 - x | + 3 x + C$
(4) $- 12 \ln | 1 - x | + 3 x + C$

If $f \left( \frac { x - 4 } { x + 2 } \right) = 2 x + 1 , ( x \in R - \{ 1 , - 2 \} )$, then $\int f ( x ) d x$ is equal to\\
(1) $12 \ln | 1 - x | - 3 x + C$\\
(2) $- 12 \ln | 1 - x | - 3 x + C$\\
(3) $12 \ln | 1 - x | + 3 x + C$\\
(4) $- 12 \ln | 1 - x | + 3 x + C$

Paper Questions

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