If the line, $\frac { x - 1 } { 2 } = \frac { y + 1 } { 3 } = \frac { z - 2 } { 4 }$ meets the plane, $x + 2 y + 3 z = 15$ at a point $P$, then the distance of $P$ from the origin is,\\
(1) $2 \sqrt { 5 }$\\
(2) $\frac { 9 } { 2 }$\\
(3) $\frac { \sqrt { 5 } } { 2 }$\\
(4) $\frac { 7 } { 2 }$