jee-main 2019 Q83

jee-main · India · session2_09apr_shift1 Integration by Substitution Substitution to Transform Integral Form (Show Transformed Expression)

$\int \sec ^ { 2 } x \cdot \cot ^ { \frac { 4 } { 3 } } x \, d x$ is equal to
(1) $3 \tan ^ { - \frac { 1 } { 3 } } x + C$
(2) $- \frac { 3 } { 4 } \tan ^ { - \frac { 4 } { 3 } } x + C$
(3) $- 3 \tan ^ { - \frac { 1 } { 3 } } x + C$
(4) $- 3 \cot ^ { - \frac { 1 } { 3 } } x + C$

$\int \sec ^ { 2 } x \cdot \cot ^ { \frac { 4 } { 3 } } x \, d x$ is equal to\\
(1) $3 \tan ^ { - \frac { 1 } { 3 } } x + C$\\
(2) $- \frac { 3 } { 4 } \tan ^ { - \frac { 4 } { 3 } } x + C$\\
(3) $- 3 \tan ^ { - \frac { 1 } { 3 } } x + C$\\
(4) $- 3 \cot ^ { - \frac { 1 } { 3 } } x + C$

Paper Questions

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