jee-main 2019 Q89

jee-main · India · session2_09apr_shift2 Vectors: Lines & Planes Distance Computation (Point-to-Plane or Line-to-Line)

Let $P$ be the plane, which contains the line of intersection of the planes, $x + y + z - 6 = 0$ and $2 x + 3 y + z + 5 = 0$ and it is perpendicular to the $x y$-plane. Then the distance of the point $( 0,0,256 )$ from $P$ is equal to:
(1) $205 \sqrt { 5 }$ units
(2) $\frac { 17 } { \sqrt { 5 } }$ units
(3) $\frac { 11 } { \sqrt { 5 } }$ units
(4) $63 \sqrt { 5 }$ units

Let $P$ be the plane, which contains the line of intersection of the planes, $x + y + z - 6 = 0$ and $2 x + 3 y + z + 5 = 0$ and it is perpendicular to the $x y$-plane. Then the distance of the point $( 0,0,256 )$ from $P$ is equal to:\\
(1) $205 \sqrt { 5 }$ units\\
(2) $\frac { 17 } { \sqrt { 5 } }$ units\\
(3) $\frac { 11 } { \sqrt { 5 } }$ units\\
(4) $63 \sqrt { 5 }$ units

Paper Questions

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