If the center and radius of the circle $\left|\frac{z - 2}{z - 3}\right| = 2$ are respectively $(\alpha, \beta)$ and $\gamma$, then $3\alpha + \beta + \gamma$ is equal to (1) 11 (2) 9 (3) 10 (4) 12
If the center and radius of the circle $\left|\frac{z - 2}{z - 3}\right| = 2$ are respectively $(\alpha, \beta)$ and $\gamma$, then $3\alpha + \beta + \gamma$ is equal to\\
(1) 11\\
(2) 9\\
(3) 10\\
(4) 12