jee-main 2023 Q78

jee-main · India · session1_01feb_shift1 Vectors 3D & Lines Line-Plane Intersection

Let the image of the point $P(2, -1, 3)$ in the plane $x + 2y - z = 0$ be $Q$. Then the distance of the plane $3x + 2y + z + 29 = 0$ from the point $Q$ is
(1) $\frac{22\sqrt{2}}{7}$
(2) $\frac{24\sqrt{2}}{7}$
(3) $2\sqrt{14}$
(4) $3\sqrt{14}$

Let the image of the point $P(2, -1, 3)$ in the plane $x + 2y - z = 0$ be $Q$. Then the distance of the plane $3x + 2y + z + 29 = 0$ from the point $Q$ is\\
(1) $\frac{22\sqrt{2}}{7}$\\
(2) $\frac{24\sqrt{2}}{7}$\\
(3) $2\sqrt{14}$\\
(4) $3\sqrt{14}$

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