The shortest distance between the lines $\frac{x-5}{1} = \frac{y-2}{2} = \frac{z-4}{-3}$ and $\frac{x+3}{1} = \frac{y+5}{4} = \frac{z-1}{-5}$ is\\ (1) $7\sqrt{3}$\\ (2) $5\sqrt{3}$\\ (3) $6\sqrt{3}$\\ (4) $4\sqrt{3}$