jee-main 2023 Q69

jee-main · India · session1_25jan_shift1 Straight Lines & Coordinate Geometry Point-to-Line Distance Computation
The distance of the point $( 6 , - 2 \sqrt { 2 } )$ from the common tangent $y = m x + c , m > 0$, of the curves $x = 2 y ^ { 2 }$ and $x = 1 + y ^ { 2 }$ is
(1) $\frac { 1 } { 3 }$
(2) 5
(3) $\frac { 14 } { 3 }$
(4) $5 \sqrt { 3 }$
The distance of the point $( 6 , - 2 \sqrt { 2 } )$ from the common tangent $y = m x + c , m > 0$, of the curves $x = 2 y ^ { 2 }$ and $x = 1 + y ^ { 2 }$ is\\
(1) $\frac { 1 } { 3 }$\\
(2) 5\\
(3) $\frac { 14 } { 3 }$\\
(4) $5 \sqrt { 3 }$